Soal Matriks Kelas 11
soal matriks kelas 11
1. soal matriks kelas 11
Jawaban:
A.
[tex] \binom{12 \: \: \: 18}{17 \: \: - 8} [/tex]
Penjelasan dengan langkah-langkah:Ada di lampiran ya....
Mapel : MatematikaKelas : XIMateri : MatriksKode soal : 2[tex]{\boxed{\boxed{\color{Magenta} Semoga \ membantu \ dan \ semangat \ belajarnya :)}}}[/tex]
2. Soal matriks kelas 11
maksudnya soal matriks itu apa ya?
3. Soal matriks kelas 11
[tex]\text{AC}~=~\text{B}[/tex]
[tex][\begin{array}{ccc}2&-1\\3&-4\end{array}].\text{C}~=~[\begin{array}{ccc}3&2\\-13&-7\end{array}][/tex]
[tex]\text{C}~=~[\begin{array}{ccc}2&-1\\3&-4\end{array}]^{-1}[\begin{array}{ccc}3&2\\-13&-7\end{array}][/tex]
[tex]\text{C}~=~\frac{1}{(2).(-4)~-~ (-1).(3)}[\begin{array}{ccc}-4&1\\-3&2\end{array}][\begin{array}{ccc}3&2\\-13&-7\end{array}][/tex]
[tex]\text{C}~=~-\frac{1}{5}[\begin{array}{ccc}-4&1\\-3&2\end{array}][\begin{array}{ccc}3&2\\-13&-7\end{array}][/tex]
[tex]\text{C}~=~[\begin{array}{ccc}\frac{4}{5}&-\frac{1}{5}\\\frac{3}{5}&-\frac{2}{5}\end{array}][\begin{array}{ccc}3&2\\-13&-7\end{array}][/tex]
[tex]\text{C}~=~[\begin{array}{ccc}(\frac{4}{5}).(3)~+~(-\frac{1}{5}).(-13)&(\frac{4}{5}).(2)~+~(-\frac{1}{5}).(-7)\\(\frac{3}{5}).(3)~+~(-\frac{2}{5}).(-13)&(\frac{3}{5}).(2)~+~(-\frac{2}{5}).(-7)\end{array}][/tex]
[tex]\text{C}~=~[\begin{array}{ccc}\frac{12}{5}~+~\frac{13}{5}&\frac{8}{5}~+~\frac{7}{5}\\\frac{9}{5}~+~\frac{26}{5}&\frac{6}{5}~+~\frac{14}{5}\end{array}][/tex]
[tex]\text{C}~=~[\begin{array}{ccc}\frac{25}{5}&\frac{15}{5}\\\frac{35}{5}&\frac{20}{5}\end{array}][/tex]
[tex]\text{C}~=~[\begin{array}{ccc}5&3\\7&4\end{array}][/tex]
[tex]\text{C}^{-1}~=~\frac{1}{(5).(4)~-~(3).(7)}[\begin{array}{ccc}4&-3\\-7&5\end{array}][/tex]
[tex]\text{C}^{-1}~=~\frac{1}{-1}[\begin{array}{ccc}4&-3\\-7&5\end{array}][/tex]
[tex]\text{C}^{-1}~=~-[\begin{array}{ccc}4&-3\\-7&5\end{array}][/tex]
[tex]\text{C}^{-1}~=~[\begin{array}{ccc}-4&3\\7&-5\end{array}][/tex]
[tex]\to\boxed{\boxed{(\text{C}^{-1})^\text{T}~=~[\begin{array}{ccc}-4&7\\3&-5\end{array}]}}[/tex]
4. 1 soal aja.. (matriks kelas 11)
semoga membantu.. good luck!!
5. tolong yg bisa soal matriks soal kelas 11
Maaf klo slh. Semoga membantu
Penjelasan dengan langkah-langkah:
[tex]{\pink{\fcolorbox{blue}{black}{\boxed{\bold{\blue{by }}}\boxed{\mathfrak{}\red{ pushrank21}}}}}[/tex]
6. 1 soal ini aja ( matriks kelas 11 )
• 3p = p + 4
3p - p = 4
2p = 4
p = 2
• 3q = 6 + p + q
masukkan p = 2
3q - q = 6 + 2
2q = 8
q = 4
• 3s = 2s + 3
3s - 2s = 3
s = 3
• 3r = - 1 + r + s
3r - r = -1 + s
masukkan s = 3
2r = -1 + 3
2r = 2
r = 1
7. SOAL UN TENTANG MATRIKS KELAS 11
Jawab:
Penjelasan dengan langkah-langkah:
matriks
kesamaan
elemen seletak bernilai sama
___
soal
[tex]\sf A = \left[\begin{array}{ccc}-4&2x- 2\\-2x+11z &6\end{array}\right] ~ dan~ B = \left[\begin{array}{ccc}-2&-5\\26 &z-y\end{array}\right][/tex]
Jika A = 2B , maka
2x-2 = 2(-5)
2x - 2 = -10
2x = -8
x= - 4
-2x + 11 z = 2(26)
-2(-4) + 11 z = 52
8 + 11 z = 52
11z = 44
z = 4
6= 2 (z-y)
3 = z - y
3 = 4 - y
y = 1
nilai (x - 2y + z) =
= (-4) - 2(1) + (4)
= - 2
8. Ini jawabannya apa ya? Soal matriks kelas 11
Penjelasan dengan langkah-langkah:
Jawabannyaadadiatassemogabisamembantu
9. SOAL MATRIKS KELAS 11 SMK
Jawaban:
Jawabannya adalah B.
Penjelasan ada pada gambar⬆️⬆️⬆️
10. soal matriks kelas 11 ,dengan penjelasan
Jawab:
2 3
-1 4
Penjelasan dengan langkah-langkah:
At = baris jadi kolom
kolom jadi baris
At = 2 3
-1 4
11. 1 soal ini aja (matriks kelas 11)
Materi : Matriks
Jawaban terlampir
Semoga membantu
jawaban di lampiran ya
12. matriks kelas 11 soal dilampiran
Jawab:
Penjelasan dengan langkah-langkah:
13. 1 soal ini aja ( matriks kelas 11 )
semoga membantu yaaaa
14. soal matriks kelas 11, ada yang bisa gaa?
SEMOGA BISA MEMBANTU NYA*_*
15. Soal matriks kelas 11
Jawab: D
Penjelasan :
B.A=C
[tex]B. \left[\begin{array}{ccc}-5&7\\1&-3\end{array}\right] = \left[\begin{array}{ccc}13&-23\\-26&46\end{array}\right][/tex]
[tex]\left[\begin{array}{ccc}a&b\\c&d\end{array}\right].\left[\begin{array}{ccc}-5&7\\1&-3\end{array}\right] = \left[\begin{array}{ccc}13&-23\\-26&46\end{array}\right][/tex]
[tex]\left[\begin{array}{ccc}a.(-5)+b.(1) &a.(7)+b.(-3)\\c.(-5)+d.(1)&c.(7)+d(-3)\end{array}\right] = \left[\begin{array}{ccc}13&-23\\-26&46\end{array}\right][/tex]
[tex]a(-5)+b(1)=13\\a(7)+b(-3)=-23[/tex] [tex]|kali 3\\|kali (-1)[/tex] [tex]|\\|[/tex] [tex]-15a+3b=39\\-7a+3b=23[/tex] (kemudian dikurangi)
[tex]-8a=16\\a=-2[/tex]
[tex]-7a+3b=23\\-7(-2)+3b=23\\b=3\\[/tex]
[tex]c(-5)+d(1)=-26\\c(7)+d(-3)=46[/tex] [tex]|\\|[/tex] [tex]kali 3\\kali (-1)[/tex] [tex]|\\|[/tex] [tex]-15c+3d=-78\\-7c+3d=-46[/tex] (kemudian dikurangi)
[tex]-8c=-32\\c=4[/tex]
[tex]-7c+3d=-46\\-7(4)+3d=-46\\d=-6\\[/tex]
sehingga dapat disimpulkan matrix B = [tex]\left[\begin{array}{ccc}-2&3\\4&-6\end{array}\right][/tex]
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